document.write( "Question 185717: A bus leaves a station in Phila at 1 pm and travels east on the pa turnpike traveling at an avg 40 miles per hour. A motorcycle leaves the same bus station at 1:30 pm and travels the same route as the bus. If the motorcycle avgs 60 mph, at what time will the motorcycle pass the bus?\r
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document.write( "I need to define the variables and create 2 equations. I have the answer of 2:30 but cannot derive the equations I need to get to this answer.\r
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document.write( "Even my parents can't figure it out. \n" );
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Algebra.Com's Answer #139387 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 40T=60(T-.5) \n" ); document.write( "40T=60T-30 \n" ); document.write( "40T-60T=-30 \n" ); document.write( "-20T=-30 \n" ); document.write( "T=-30/-20 \n" ); document.write( "T=1.5 HOURS AFTER THE BUS LEAVES THE MOTORCYCLE WILL PASS THE BUS. \n" ); document.write( "1:00+1:30=2:30 HOUR OF THE PASSING. \n" ); document.write( "PROOF: \n" ); document.write( "40*1.5=60(1.5-.5) \n" ); document.write( "60=60*1 \n" ); document.write( "60=60 \n" ); document.write( " |