document.write( "Question 185796This question is from textbook Elementary Statistics
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document.write( ": 22.) One out of four Americans over age 55 has eaten pizza for breakfast. If a sample of 10 Americans over age 55 is selected at random, find the probability that at most 3 have eaten pizza for breakfast.\r
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Algebra.Com's Answer #139335 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! One out of four Americans over age 55 has eaten pizza for breakfast. If a sample of 10 Americans over age 55 is selected at random, find the probability that at most 3 have eaten pizza for breakfast. \n" ); document.write( "---------------- \n" ); document.write( "It's binomial because each person either has or has not eaten pizza. \n" ); document.write( "--------------- \n" ); document.write( "n = 10 ; p = 1/4 ; 0<=x<=3 \n" ); document.write( "------------------------------- \n" ); document.write( "On a TI-83 use binomcdf(10,0.25,3) to get 0.7759 \n" ); document.write( "==================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |