document.write( "Question 185796This question is from textbook Elementary Statistics
\n" ); document.write( ": 22.) One out of four Americans over age 55 has eaten pizza for breakfast. If a sample of 10 Americans over age 55 is selected at random, find the probability that at most 3 have eaten pizza for breakfast.\r
\n" ); document.write( "\n" ); document.write( "Thanks!
\n" ); document.write( "

Algebra.Com's Answer #139335 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
One out of four Americans over age 55 has eaten pizza for breakfast. If a sample of 10 Americans over age 55 is selected at random, find the probability that at most 3 have eaten pizza for breakfast.
\n" ); document.write( "----------------
\n" ); document.write( "It's binomial because each person either has or has not eaten pizza.
\n" ); document.write( "---------------
\n" ); document.write( "n = 10 ; p = 1/4 ; 0<=x<=3
\n" ); document.write( "-------------------------------
\n" ); document.write( "On a TI-83 use binomcdf(10,0.25,3) to get 0.7759
\n" ); document.write( "====================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );