document.write( "Question 25847: Hi! I was wondering if you could help me with this problem please: A commercial jet can fly from San Francisco to Dallas in 3 hours. A private jet can make the same trip in 3 1/2 hours. If the two planes leave San Francisco at noon, after how many hours is the private jet twice as far from Dallas as the commercial jet?\r
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Algebra.Com's Answer #13932 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Hi! I was wondering if you could help me with this problem please: A commercial jet can fly from San Francisco to Dallas in 3 hours. \n" ); document.write( "LET THE SPEED OF COMMERCIAL JET (CJ)=S \n" ); document.write( "IN 3 HRS IT CAN FLY =3S MILES = DISTANCE FROM SFC TO DALLAS \n" ); document.write( "A private jet(PJ) can make the same trip in 3 1/2 hours. \n" ); document.write( "SO SPEED OF PRIVATE JET =3S/3.5 \n" ); document.write( "If the two planes leave San Francisco at noon, after how many hours is the private jet twice as far from Dallas as the commercial jet? \n" ); document.write( "LET US ASSUME THAT AFTER T HOURS the private jet WILL BE twice as far from Dallas as the commercial jet \n" ); document.write( "DISTANCE TRAVELLED BY CJ IN T HRS = ST MILES..ITS DISTANCE FROM DALLAS \n" ); document.write( "=3S-ST \n" ); document.write( "DISTANCE TRAVELLED BY PJ IN T HRS =3ST/3.5 MILES...ITS DISTANCE FROM DALLAS \n" ); document.write( "=3S-3ST/3.5 \n" ); document.write( "WE ARE GIVEN THAT \n" ); document.write( " 2(3S-ST)=3S-3ST/3.5 \n" ); document.write( "2(3-T)=3-3T/3.5 \n" ); document.write( "21-7T=10.5-3T \n" ); document.write( "21-10.5=7T-3T=4T \n" ); document.write( "10.5=4T \n" ); document.write( "T=10.5/4=2.625 HRS.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |