document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185683>Question 185683</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1602773033/algebrahomeworkh>saxon algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve 6cos theta -3 square root 2 =0, for 0 degrees is less than or equal to theta is less than or equal to 360 degrees. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139270 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve 6cos(theta) -3 square root(2) = 0, for 0 degrees is less than or equal to theta is less than or equal to 360 degrees.<BR>\n" );
document.write( "--------------------------------<BR>\n" );
document.write( "6cos(theta) -3 square root(2) = 0<BR>\n" );
document.write( "Divide thru by 3 to get:<BR>\n" );
document.write( "2cos(theta) - square root(2) = 0<BR>\n" );
document.write( "cos(theta) = (sqrt(2))/2<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "Take the inverse cosine or arccos to get:<BR>\n" );
document.write( "theta = 45 degrees or theta = 315 degrees.<BR>\n" );
document.write( "============================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );