document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185610>Question 185610</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve Problems Using Linear Systems<BR>\n" );
document.write( "14. A metal alloy is 25% copper. Another metal alloy is 50% copper. How much of each should be used to make 500 g of an alloy that is 45% copper?<BR>\n" );
document.write( "(The answer is: 100 g of metal alloy that is 25% copper, 400 g of metal alloy that is 50% copper, but i dont know how to  solve it?) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139255 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139255\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .50X+.25(500-X)=.45*500<BR>\n" );
document.write( ".50X+125-.25X=225<BR>\n" );
document.write( ".25X=225-125<BR>\n" );
document.write( ".25X=100<BR>\n" );
document.write( "X=100/.25<BR>\n" );
document.write( "X=400 G OF 50% COPPER IS USED.<BR>\n" );
document.write( "500-400=100 G OF 25% COPPER IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".50*400+.25*100=.45*500<BR>\n" );
document.write( "200+25=225<BR>\n" );
document.write( "225=225 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );