document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185643>Question 185643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve Problems Using Linear Systems<BR>\n" );
document.write( "11. What volume, in mililitres, of a 60% hydrochloric acid solution must be added to 100 mL of a 30% hydrochloric acid solution to make a 36% hydrochloric acid solution?<BR>\n" );
document.write( "Can you help me please? Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139240 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .6X+.3*100=.36(100+X)<BR>\n" );
document.write( ".6X+30=36+.36X<BR>\n" );
document.write( ".6X-.36X=36-30<BR>\n" );
document.write( ".24X=6<BR>\n" );
document.write( "X=6/.24<BR>\n" );
document.write( "X=25 ML OF 60% ACID IS NEEDED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".6*25+.3*100=.36(100+25)<BR>\n" );
document.write( "15+30=.36*125<BR>\n" );
document.write( "45=45<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );