document.write( "Question 185643: Solve Problems Using Linear Systems
\n" ); document.write( "11. What volume, in mililitres, of a 60% hydrochloric acid solution must be added to 100 mL of a 30% hydrochloric acid solution to make a 36% hydrochloric acid solution?
\n" ); document.write( "Can you help me please? Thanks \n" ); document.write( "

Algebra.Com's Answer #139239 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let x = the number of ml. of 60% hydrochloric acid required.
\n" ); document.write( "The amount of hydrochloric acid in x ml. of 60% acid solution can be expressed as 0.6x ml, and this is to be added to 100 ml. of 30% hydrochloric acid solution which, of course, contains 0.3(100) ml of hydrochloric acid.
\n" ); document.write( "The sum of these is to equal (100+x) ml. of 36% hydrochloric acid solution which contains 0.36(100-x) ml of hydrochloric acid.
\n" ); document.write( "Now you can set up the necessary equation to solve for x.
\n" ); document.write( "0.6x+0.3(100) = 0.36(100+x)
\n" ); document.write( "0.6x+30 = 36+0.36x Subtract 30 from both sides.
\n" ); document.write( "0.6x = 6+0.36x Now subtract 0.36x from both sides.
\n" ); document.write( "0.24x = 6 Finally, divide both sides by 0.24
\n" ); document.write( "x = 25
\n" ); document.write( "25 ml. of 60% hydrochloric acid solution need to be add to 100 ml. of 30% hydrochloric acid solution to obtain 125 ml. of 36% hydrochloric acid solution. \n" ); document.write( "

\n" );