document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185642>Question 185642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve Problems Using Linear Systems<BR>\n" );
document.write( "10. White vinegar is a solution of acetic acid in water. There are two strengths of white vinegar-a 5% solution and a 10% solution. How many mililitres of each solution must be mixed to make 50 mL of a 9% vinegar solution?<BR>\n" );
document.write( "Can you please help me with these problem? Thank you very much!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139235 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .10x+.05(50-x)=.09*50<BR>\n" );
document.write( ".10x+2.5-.05x=4.5<BR>\n" );
document.write( ".05x=4.5-2.5<BR>\n" );
document.write( ".05x=2<BR>\n" );
document.write( "x=2/.05<BR>\n" );
document.write( "x=40 ml of 10% vinegar is used.<BR>\n" );
document.write( "50-40=10 ml of 5% vinegar is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".10*40+.05*10=.09*50<BR>\n" );
document.write( "4+.5=4.5<BR>\n" );
document.write( "4.5=4.5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );