document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185618>Question 185618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling 100 MPH and train B is traveling at 104 MPH. Train A passes a station at 9:20P.M. If train B passes the station at 9:50P.M. at what time will train B catch up to train A. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139225 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139225\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling 100 MPH and train B is traveling at 104 MPH. Train A passes a station at 9:20P.M. If train B passes the station at 9:50P.M. at what time will train B catch up to train A.<BR>\n" );
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document.write( "B passes the station 1/2 hour after A, so A is 50 miles away (100 mph times 1/2 hour).<BR>\n" );
document.write( "A is approaching B at 4 mph (104 - 100).  To gain 50 miles at 4 mph will take 50/4 = 12.5 hours.<BR>\n" );
document.write( "9:50 PM + 12.5 hours --> 1020 AM the next day. </SPAN>\n" );
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