document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185582>Question 185582</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The mass of a molecule of a certain chemical compound is 2.45*10 to the power of -22 g. If each molecule is made up of two carbon atoms and six oxygen atoms and the mass of one oxygen atom is 1/3 that of a carbon atom, find the mass of an oxygen atom.  \r<BR>\n" );
document.write( "\n" );
document.write( "The answer is 2.04 * 10 to the power of -23 g.  I do not understand this in terms of showing working. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139220 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let c=carbon & g=oxygen<BR>\n" );
document.write( "2c+6/3g=2.45*10^-22<BR>\n" );
document.write( "2c+2g=2.45*10^-22 there are equal masses of oxygen and carbon in the compound.<BR>\n" );
document.write( "0.5*2.45*10^-22<BR>\n" );
document.write( "=1.225*10^-22 mass of oxygen in the compound.<BR>\n" );
document.write( "(1/6)*1.225*10^-22 There were 6 oxygen atoms in the compound<BR>\n" );
document.write( "=.2041667...*10^-22<BR>\n" );
document.write( "=2.04...*10^-23 Mass of oxygen.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );