document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185586>Question 185586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tickets for a concert were sold to adults for $3 and children for $2.  If the total receipts were $824 and twice as many adult tickets were sold as childrens tickets how many of each were sold?\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139219 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A = the number of adult tickets sold and C = the number of children's tickets sold.<BR>\n" );
document.write( "From the problem description, you are told:<BR>\n" );
document.write( "A = 2C \"...twice as many adult tickets were sold as children's tickets...\"<BR>\n" );
document.write( "The cost of the adult tickets can be expressed as ($3)A while the cost of the children's tickets can be expressed as ($2)C, so we can set up the equation for solving as follows:<BR>\n" );
document.write( "($3)A+($2)C = $824 You can dispense with the $ signs and just work with the numbers:<BR>\n" );
document.write( "3A+2C = 824 Substitute, from above, A = 2C<BR>\n" );
document.write( "3A+A = 824<BR>\n" );
document.write( "4A = 824<BR>\n" );
document.write( "A = 206 and C = A/2 = 103<BR>\n" );
document.write( "So 206 adult and 103 children's tickets were sold.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );