document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185570>Question 185570</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ratio of surface areas of two cubes is 1:4. find the ratio of their volumes. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139213 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139213\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ratio of surface areas of two cubes is 1:4. find the ratio of their volumes.<BR>\n" );
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document.write( "Surface area of a cube = 6s^2 where s is the length of a side<BR>\n" );
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document.write( "Let the smaller surface area be 6s^2, where s=1<BR>\n" );
document.write( "Then the larger surface area is 4(6s^2) = 6(4s^2) = 6(2s)^2, where side = 2\r<BR>\n" );
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document.write( "So, smaller cube has volume s^3<BR>\n" );
document.write( "and larger cube has volumne (2s)^3 = 8s^3<BR>\n" );
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document.write( "Ratio of their volumnes is 1:8<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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