document.write( "Question 185531: Cant figure this out. Help Please! :)\r
\n" ); document.write( "\n" ); document.write( "The measure of the second angle of a triangle is 50 degrees more than that of the first. The measure of the third angle is 10 degrees less than twice the first. Find the measures of the angles.
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Algebra.Com's Answer #139187 by jim_thompson5910(35256)\"\" \"About 
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Let \"x\" be the measure of the first angle\r
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\n" ); document.write( "\n" ); document.write( "Since \"The measure of the second angle of a triangle is 50 degrees more than that of the first.\", this means that the second angle is \"x%2B50\" (ie add 50 to the measure of the first angle). Also, because the \"measure of the third angle is 10 degrees less than twice the first.\", this tells us that \"2x-10\"\r
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\n" ); document.write( "\n" ); document.write( "Now remember, for EVERY triangle, the sum of their angles is 180 degrees. So this means that\r
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\n" ); document.write( "\n" ); document.write( "Angle 1 + Angle 2 + Angle 3 = 180\r
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\n" ); document.write( "\n" ); document.write( "which becomes\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%29%2B%28x%2B50%29%2B%282x-10%29=180\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%29%2B%28x%2B50%29%2B%282x-10%29=180\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"4x%2B40=180\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"4x=180-40\" Subtract \"40\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"4x=140\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28140%29%2F%284%29\" Divide both sides by \"4\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=35\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=35\" \r
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\n" ); document.write( "\n" ); document.write( "So the first angle is \"x=35\" \r
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\n" ); document.write( "\n" ); document.write( "the second angle is \"35%2B50=85\"\r
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\n" ); document.write( "\n" ); document.write( "and the third angle is \"2%2835%29-10=70-10=60\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, the measures of the three angles are: 35, 85, and 60 degrees
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