document.write( "Question 185518: can someone please help me solve this. thanks\r
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document.write( "From a group of 18 customers,5 are to be chosen to receive a special gift. Assuming that the order in which the customers are chosen is irrelevant, how many groups of 5 customers can be chosen? \r
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Algebra.Com's Answer #139172 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! can someone please help me solve this. thanks \n" ); document.write( "From a group of 18 customers,5 are to be chosen to receive a special gift. Assuming that the order in which the customers are chosen is irrelevant, how many groups of 5 customers can be chosen? \n" ); document.write( "------------------- \n" ); document.write( "The 1st one chosen can be one of 18, the 2nd 1/17, 3rd 1/16, etc., so there are 18*17*16*15*14 possibilities. \n" ); document.write( "But, since ABCDE is the same group as ADCEB, we have to divide by 5*4*3*2*1, since each of the had that many chances to be picked. \n" ); document.write( "--------------------- \n" ); document.write( "So it's 18*17*16*15*14/5*4*3*2*1 = 1028190/120 \n" ); document.write( "= 8568 possibilities \n" ); document.write( "---------------- \n" ); document.write( "This is 18!/((18-5)!*5!), btw \n" ); document.write( " |