document.write( "Question 185512: Another story problem I can't seem to understand.\r
\n" ); document.write( "\n" ); document.write( "Paul has $1.47 in change consisting of pennies, nickels and quarters. He has three more pennies than quarters and one more nickel than pennies. How many of each coin does he have?
\n" ); document.write( "

Algebra.Com's Answer #139165 by jnaert08(2)\"\" \"About 
You can put this solution on YOUR website!
Okay, so you know he has 1.47, right? This consists of pennies, nickles and quarters. So keep in mind that this is .01, .05, and .25 amounts. \r
\n" ); document.write( "\n" ); document.write( "3+q=p (three more pennies than quarters)
\n" ); document.write( "1+p=n (one more nickel than pennies)\r
\n" ); document.write( "\n" ); document.write( "where p is the number of pennies (not the total cost of the pennies)
\n" ); document.write( "n is the number of nickels
\n" ); document.write( "and q is the number of quarters\r
\n" ); document.write( "\n" ); document.write( "The way I would start this out is plug and chug and then see what to do from there. \r
\n" ); document.write( "\n" ); document.write( "If you had 2 quarters, then that would be .50 cents already taken care of. And with the 3+q=p equation, you would find out that that would mean 3+2=p, so there are 5 pennies. 5*.01=5. So thats .55 cents total taken care of. And then 1+p=n, so 1+5=n, so n=6. so then you multiple 6*.05 and and thats .30, so that's .85 cents taken care of and you needed 1.47. This is much easier once you get the hang of it, and especially if you have a calculator.\r
\n" ); document.write( "\n" ); document.write( "4 quarters = 1.00
\n" ); document.write( "3+4=p, so 7 pennies. 7*.01= .07
\n" ); document.write( "1+7=n, so 8 nickels. 8*.05= .40\r
\n" ); document.write( "\n" ); document.write( "So then you add 1.00 plus .07 plus .40, which equals 1.47!\r
\n" ); document.write( "\n" ); document.write( "So that means there were
\n" ); document.write( "4 quarters
\n" ); document.write( "7 pennies
\n" ); document.write( "and 8 nickels!
\n" ); document.write( "
\n" );