document.write( "Question 185467: b) HoHalf life of silicon 32 is 710 years. If a sample has 100 grams right now: a) How much will be present in 600 years? w much was present in 1809? \n" ); document.write( "
Algebra.Com's Answer #139152 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Half life of silicon 32 is 710 years. If a sample has 100 grams right now: \n" ); document.write( "a) How much will be present in 600 years? \n" ); document.write( "; \n" ); document.write( "The half life equation: A = Ao*2^(-t/h) \n" ); document.write( "Where \n" ); document.write( "A = Resulting amt after t years \n" ); document.write( "Ao = initial amt (t=0) \n" ); document.write( "t = time in years \n" ); document.write( "h = half life of substance in years \n" ); document.write( "; \n" ); document.write( "A = 100* 2^(-600/710) \n" ); document.write( "Find 2^(-60/71) on a calc \n" ); document.write( "A = 100 * .55668 \n" ); document.write( "A = 55.67 grms after 600 yrs \n" ); document.write( ": \n" ); document.write( "b) How much was present in 1809: \n" ); document.write( "that would be 2009 - 1809 = 200 years ago; we want to Find Ao 200 yrs ago \n" ); document.write( ": \n" ); document.write( "100 = Ao* 2^(-200/710) \n" ); document.write( "Find 2^(-20/71) on a calc \n" ); document.write( "100 = .8226*Ao \n" ); document.write( "Ao = 100/.8226 \n" ); document.write( "Ao = 121.56 grms were present 200 yrs ago \n" ); document.write( " |