document.write( "Question 171193This question is from textbook
\n" ); document.write( ": A club consists of 10 members. In how many different ways can a group of 3 people be selected to go on a European trip?\r
\n" ); document.write( "\n" ); document.write( "I came up with the answer of 9\r
\n" ); document.write( "\n" ); document.write( "Is that correct?
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Algebra.Com's Answer #139147 by Alan3354(69443)\"\" \"About 
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A club consists of 10 members. In how many different ways can a group of 3 people be selected to go on a European trip?
\n" ); document.write( "I came up with the answer of 9
\n" ); document.write( "Is that correct?
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\n" ); document.write( "How did you get 9?
\n" ); document.write( "To pick the 1st person, there are 10 to choose from.
\n" ); document.write( "For the 2nd, there are 9, and 8 for the 3rd.
\n" ); document.write( "That's 10*9*8 = 720 possibilities.
\n" ); document.write( "But, since a person could be chosen 1, 2 or 3rd to form the same group, that is,
\n" ); document.write( "ABC is the same as BCA and BAC, you have to divide by 3*2*1 = 6.
\n" ); document.write( "So the # of different groups is 720/6 = 120.
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