document.write( "Question 25850: I'm just stuck on this easy question. I know I just use the LCD; but I keep getting stuck.
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document.write( "(x +1) + (x+2)=2 The (x+1) is over 3 and the (x+2) is over 7, so they are two fractions being added but I couldn't get it to look right on this screen.\r
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document.write( "I have tried multiplying the whole equation by 21; isn' that correct? i need some help. \n" );
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Algebra.Com's Answer #13913 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The LCD=21, so you multiply the first equation by 7, the second equation by 3; \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Now multiply each side by 21; \n" ); document.write( "10x+13=42 \n" ); document.write( "10x=42-13 \n" ); document.write( "10x=29 \n" ); document.write( "x=2.9 \n" ); document.write( "Hope this helps \n" ); document.write( "=) \n" ); document.write( " |