document.write( "Question 185156: Hi:) I need some help:)\r
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document.write( "Solve for x:
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document.write( "1) logbase[5](x+1)+logbase[5](x-2)=logbase[5] 4
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document.write( "2) 1/3 logbase[3] 27+logbase[3] x = 4^(1/2)
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document.write( "3) logbase[2](x-6)+logbase[2](x)=4
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document.write( "4) logbase[4](2x+1)-logbase[4](x-2)=1 \n" );
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Algebra.Com's Answer #139099 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! You will need to apply \"log rules\". \n" ); document.write( "You can review them at: \n" ); document.write( "http://www.purplemath.com/modules/logrules.htm \n" ); document.write( ". \n" ); document.write( " 1) logbase[5](x+1)+logbase[5](x-2)=logbase[5] 4 \n" ); document.write( "logbase[5](x+1)(x-2)=logbase[5] 4 \n" ); document.write( "logbase[5](x^2-x-2)=logbase[5] 4 \n" ); document.write( "x^2-x-2= 4 \n" ); document.write( "x^2-x-6= 0 \n" ); document.write( "(x-3)(x+2) = 0 \n" ); document.write( "x = {3,-2} \n" ); document.write( ". \n" ); document.write( " 2) 1/3 logbase[3] 27+logbase[3] x = 4^(1/2) \n" ); document.write( "logbase[3] 27^(1/3) +logbase[3] x = 4^(1/2) \n" ); document.write( "logbase[3] 3 +logbase[3] x = 2 \n" ); document.write( "logbase[3] 3x = 2 \n" ); document.write( "3x = 3^2 \n" ); document.write( "3x = 9 \n" ); document.write( "x = 3 \n" ); document.write( ". \n" ); document.write( " 3) logbase[2](x-6)+logbase[2](x)=4 \n" ); document.write( "logbase[2](x-6)(x)=4 \n" ); document.write( "(x-6)(x)=2^4 \n" ); document.write( "x^2-6x=16 \n" ); document.write( "x^2-6x-16 = 0 \n" ); document.write( "(x-8)(x+2) = 0 \n" ); document.write( "x = {8,-2} \n" ); document.write( ". \n" ); document.write( " 4) logbase[4](2x+1)-logbase[4](x-2)=1 \n" ); document.write( "logbase[4](2x+1)(x-2)=1 \n" ); document.write( "(2x+1)(x-2)=4^1 \n" ); document.write( "2x^2-4x+x-2=4 \n" ); document.write( "2x^2-3x-2=4 \n" ); document.write( "2x^2-3x-6=0 \n" ); document.write( "(2x+2)(x-3) = 0 \n" ); document.write( "x={-1, 3} \n" ); document.write( " \n" ); document.write( " |