document.write( "Question 185384: Solve equation for y then find value of for the given value of x\r
\n" ); document.write( "\n" ); document.write( "2xy +1 = xy +3; x =2
\n" ); document.write( "

Algebra.Com's Answer #139082 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2xy+%2B1+=+xy+%2B3\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2xy+%2B1+-+xy+=3\" Subtract xy from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2xy-xy=3-1\" Subtract 1 from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2xy-xy=2\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%282x-x%29y=2\" Factor out the GCF \"y\" on the left side.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"xy=2\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=2%2Fx\" Divide both sides by \"x\" to isolate (solve for) \"y\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "----------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=2%2F2\" Now plug in \"x=2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=1\" Divide
\n" ); document.write( "
\n" );