document.write( "Question 25824: Hi guys, i really need your help. Could you please help me solve this problem:
\n" ); document.write( "An elevator went from the bottom to the top of a tower at an average speed of 4 m/s, remained at the top for 90 s, and then returned to the bottom at 5 m/s. If the total elapsed time was 4 1/2 minutes, how high is the tower?\r
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Algebra.Com's Answer #13907 by Paul(988) $\"\"$ $\"About$

You can put this solution on YOUR website!
4 1/2 ----> 9/2 ---> 4.5
\n" ); document.write( "4.5 --> 270s
\n" ); document.write( "270s-90s=180s
\n" ); document.write( "Let the distance be x
\n" ); document.write( "So $\"x%2F4%2Bx%2F5\"$ =180
\n" ); document.write( "The common multiple is 20
\n" ); document.write( " $\"20%28x%2F4%29%2B20%28x%2F5%29=20%28180%2F1%29\"$
\n" ); document.write( "5x+4x=3600
\n" ); document.write( "9x=3600
\n" ); document.write( "x=400\r
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\n" ); document.write( "\n" ); document.write( "Hence, the tower is 400m high.
\n" ); document.write( "Paul.
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