document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185278>Question 185278</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain reproductive element decays according to A(t) = A(0,e^-0.032t). Where t is years. How long will it take to go from 800 grams to 85 grams? (nearest year) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139064 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139064\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A certain reproductive element decays according to A(t) = A(0,e^-0.032t). Where t is years. How long will it take to go from 800 grams to 85 grams? (nearest year)<BR>\n" );
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document.write( "A(t) = A(0,e^-0.032t). \r<BR>\n" );
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document.write( "85 = 800*e^(-0.032t)\r<BR>\n" );
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document.write( "e^(-0.032t) = 0.10625\r<BR>\n" );
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document.write( "Take the natural log of both sides to get:<BR>\n" );
document.write( "-0.032t = -2.24196\r<BR>\n" );
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document.write( "t = 70 years (nearest year) </SPAN>\n" );
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