document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185367>Question 185367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three times its width. If the area of the rectangle is 192 cm^2 , find its perimeter. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #139050 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=139050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three times its width. If the area of the rectangle is 192 cm^2 , find its perimeter. <BR>\n" );
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document.write( "Let w = width<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3w = length<BR>\n" );
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document.write( "192 = w(3w)<BR>\n" );
document.write( "192 = 3w^2<BR>\n" );
document.write( "64 = w^2<BR>\n" );
document.write( "8 cm = w<BR>\n" );
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document.write( "length:<BR>\n" );
document.write( "3w = 3*8 = 24 cm <BR>\n" );
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document.write( "Therefore perimeter is:<BR>\n" );
document.write( "2(8+24) = 2(32) = 64 cm<BR>\n" );
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