document.write( "Question 185313: Solve by the Addition Method:
\n" ); document.write( "4x-5y=3y+4
\n" ); document.write( "2x+3y=2x+1
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Algebra.Com's Answer #139039 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
4x - 5y = 3y + 4
\n" ); document.write( "2x + 3y = 2x + 1
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\n" ); document.write( "Put both equation in the ax + by = c form
\n" ); document.write( "4x - 5y - 3y + 4
\n" ); document.write( "4x - 8y = 4
\n" ); document.write( "and
\n" ); document.write( "2x - 2x + 3y = 1
\n" ); document.write( "3y = 1
\n" ); document.write( "y = \"1%2F3\"
\n" ); document.write( ":
\n" ); document.write( "Substitution would work great here, but you want the addition method
\n" ); document.write( "multiply (4x - 8y = 4) by 3; and 3y=1 by 8, results:
\n" ); document.write( "12x - 24y = 12
\n" ); document.write( "0x + 24y = 8
\n" ); document.write( "----------------addition eliminates y, find x
\n" ); document.write( "12x = 20
\n" ); document.write( "x = \"20%2F12\"
\n" ); document.write( "x = \"5%2F3\"
\n" ); document.write( ":
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\n" ); document.write( "Check solutions in 1st original equation
\n" ); document.write( "4x - 5y = 3y + 4
\n" ); document.write( "4*\"5%2F3\" - 5*\"1%2F3\" = 3*\"1%2F3\" + 4
\n" ); document.write( "\"20%2F3\" - \"5%2F3\" = \"3%2F3\" + \"12%2F3\"
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