document.write( "Question 185346: This question is on Rational Expressions, and solving them using the Algebraic method to find the vertical asymptote.\r
\n" ); document.write( "\n" ); document.write( "g(x)=(x^2+x+1)/(5x^2+1) I can't figure out where to start...\r
\n" ); document.write( "\n" ); document.write( "Also simplifying (3a^2-6a)/(12-6a) What the heck is this? And where do I start and finish this crazy problem???
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Algebra.Com's Answer #139021 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
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\n" ); document.write( "\n" ); document.write( "\"g%28x%29=%28x%5E2%2Bx%2B1%29%2F%285x%5E2%2B1%29\" Start with the given function.\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2%2B1=0\" Set the denominator equal to zero. Remember, vertical asymptotes arise only when there's a division by zero\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2=-1\" Subtract 1 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=-1%2F5\" Divide both sides by 5\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%28-1%2F5%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "Remember, you CANNOT take the square root of a negative number. So this means that the value of \"x\" will be complex/imaginary. \r
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\n" ); document.write( "\n" ); document.write( "In other words, there is NO value of \"x\" that will make the denominator zero. \r
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\n" ); document.write( "\n" ); document.write( "So there are no vertical asymptotes (graph the function to verify)\r
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\n" ); document.write( "\n" ); document.write( "# 2\r
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\n" ); document.write( "\n" ); document.write( "\"%283a%5E2-6a%29%2F%2812-6a%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%283a%28a-2%29%29%2F%2812-6a%29\" Factor the numerator\r
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\n" ); document.write( "\n" ); document.write( "\"%283a%28a-2%29%29%2F%28-6%28a-2%29%29\" Factor the denominator\r
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\n" ); document.write( "\n" ); document.write( "\"-%28a%28a-2%29%29%2F%282%28a-2%29%29\" Reduce \"3%2F%28-6%29\" (the outer coefficients) to get \"-1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"-%28a%2Ahighlight%28%28a-2%29%29%29%2F%282%2Ahighlight%28%28a-2%29%29%29\" Highlight the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-%28a%2Across%28%28a-2%29%29%29%2F%282%2Across%28%28a-2%29%29%29\" Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-a%2F2\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"%283a%5E2-6a%29%2F%2812-6a%29\" simplifies to \"-a%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%283a%5E2-6a%29%2F%2812-6a%29=-a%2F2\" where \"a%3C%3E2\"
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