document.write( "Question 25817: The problem is:
\n" ); document.write( "A DVD company wants to maximize its revenue. the company now sells dvd's for $40 each and they have 6000 customers. a study suggests that for every $2.00 increase in price they will lose 200 customers. what should be the selling price to maximize the company's revenue? what will that revenue be?\r
\n" ); document.write( "\n" ); document.write( "So far I've written an equation:
\n" ); document.write( "let R= revenue
\n" ); document.write( "let x= # of $2 increases
\n" ); document.write( "R=(6000-200x)(40+x)\r
\n" ); document.write( "\n" ); document.write( "When i try to solve, I get: x=-5 and R=245000 but I know x can not be negative.
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Algebra.Com's Answer #13902 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
Let x be the $ 2 increase.
\n" ); document.write( "cost of DVD:
\n" ); document.write( "2(x+40)
\n" ); document.write( "2x+80
\n" ); document.write( "DVD sold = 6000-200x
\n" ); document.write( "(2x+80)(6000-200x)
\n" ); document.write( "-400x^2+12000x+480000-16000x
\n" ); document.write( "-400x^2-4000x+480000
\n" ); document.write( "400x^2+4000x-480000=0,x
\n" ); document.write( "x^2+40x-1200=0
\n" ); document.write( "CAN YOU SOLVE IT FROM ZTHERE if not e-mail me back.
\n" ); document.write( "you'll get x=30
\n" ); document.write( "Hence, the revenue is 30.
\n" ); document.write( "PAUL.
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