document.write( "Question 25797: Here is my question: A banker invested a portion of $10,000 at 5% interest per year and the remainder at 4% interest per year. If the banker received $470 in interest after 1 year, how much was invested at each rate?
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document.write( "I really don't get this, PLEASE HELP!!!! \n" );
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Algebra.Com's Answer #13901 by elima(1433)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the amount he invested at 5%, \n" ); document.write( "10,000-x=amount invested at 4% \n" ); document.write( "so we have; \n" ); document.write( "5%x+(10,000-x)4%=470 \n" ); document.write( "5%x+400-4%x=470 \n" ); document.write( "400+1%x=470 \n" ); document.write( "1%x=70 \n" ); document.write( "x=7000 \n" ); document.write( "So if $7,000 was invested at 5%; \n" ); document.write( "then $7,000-10,000=$3,000 \n" ); document.write( "$3,000 wasinvested at 4% \n" ); document.write( "Hope you understand \n" ); document.write( "=) \n" ); document.write( " |