document.write( "Question 25803: Ribbons costing $0.20 each are mixed with ribbons costing $0.15 each. The mixture costs $1.20. The number of $0.20 ribbons is 3/4 of the $0.15 ribbons. Find the number of each type of ribbon in the box. \r
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Algebra.Com's Answer #13899 by elima(1433)\"\" \"About 
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Let x=ribbons that cost .15
\n" ); document.write( "then \"3%2F4\"x=ribbons that cost .20
\n" ); document.write( "so we have;
\n" ); document.write( ".15x+.20\"%283%2F4%29\"=1.20
\n" ); document.write( ".15x+.15x=1.20
\n" ); document.write( ".30x=1.20
\n" ); document.write( "x=4
\n" ); document.write( "So the ribbons that cost .15 is 4;
\n" ); document.write( "and the ribbons that cost .20= \"3%2F4\"(4)=3
\n" ); document.write( "Hope you understand
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