document.write( "Question 185282: The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #138988 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L/4=2W OR L=8W \n" ); document.write( "2L+2W=160 \n" ); document.write( "2*8W+2W=160 \n" ); document.write( "16W+2W=160 \n" ); document.write( "18W=160 \n" ); document.write( "W=160/18 \n" ); document.write( "W=80/9 ANS. \n" ); document.write( "L=8*80/9 \n" ); document.write( "L=640/9 ANS. \n" ); document.write( "PROOF: \n" ); document.write( "2*640/9+2*80/9=160 \n" ); document.write( "1280/9+160/9=160 \n" ); document.write( "1440/9=160 \n" ); document.write( "160=160 \n" ); document.write( " |