document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185290>Question 185290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the domain of each of these and show how you got it. h(x)=3x^2+5-3<BR>\n" );
document.write( "m(x)=5/x^2-9   1(x)=5x-4   g(x)=7x+4/x+4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138977 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h(x)=3x^2+5-3  domain is all X, since no value of x results in an invalid h(x)<BR>\n" );
document.write( "m(x)=5/x^2-9 domain is all X except 3 and -3, since those two values of x results in a denominator that is 0. Which is not allowed<BR>\n" );
document.write( "l(x)=5x-4   domain is all X, since no value of x results in an invalid l(x)<BR>\n" );
document.write( "g(x)=7x+4/x+4 domain is all X except 4, since that value of x results in a denominator that is 0. Which is not allowed </SPAN>\n" );
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