document.write( "Question 185266: this is from a worksheet not a text book. I am grandma trying to help grandson\r
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document.write( "The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle.
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document.write( "Thank you for your valued help!! \n" );
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Algebra.Com's Answer #138970 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! Perimeter=160 = 2L+2W........eq 1 \n" ); document.write( ": \n" ); document.write( "(1/4)L=2(W)........eq 2 \n" ); document.write( ": \n" ); document.write( "rewrite eq 2 to L=4*2*W=8W....multiplied both sides by 4 \n" ); document.write( ": \n" ); document.write( "now take L's value of 8W and plug that into eq 1 \n" ); document.write( ": \n" ); document.write( "2(8W)+2W=160 \n" ); document.write( ": \n" ); document.write( "18W=160 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "L=8(8.89)= \n" ); document.write( ": \n" ); document.write( "2(71.12)+2(8.89)=142.2+17.78=159.98...rounding off caused us to be off a little \n" ); document.write( " |