document.write( "Question 185216: A new car worth $ 24,000 is depreciating in value by $ 3000 per year. Write a formular that models the car's value, y, in dollars, after x year. \n" ); document.write( "
Algebra.Com's Answer #138968 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "We can give a formula,\"Y=P-3000%28X%29\"
\n" ); document.write( "where\"system%28Y=Value_after_X_years%2CP=Present_Value%2CX=Number+of_Years%29\"
\n" ); document.write( "After 1 year:
\n" ); document.write( "\"Y=24000-3000%281%29=24000-3000\"=$21,000.00
\n" ); document.write( "After 2 years:
\n" ); document.write( "\"Y=24000-3000%282%29=24000-6000\"=$18,000.00
\n" ); document.write( "After 3 years:
\n" ); document.write( "\"Y=24000-3000%283%29=24000-9000\"=$15,000.00
\n" ); document.write( "And so forth....
\n" ); document.write( "*Note: After \"8\" years, I think it's about time to buy a NEW car. Substitute X=8 and see why?
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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