document.write( "Question 185243: Can you please help me with this word problem for some reason Im not understanding the concept of figuring these problems.\r
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\n" ); document.write( "\n" ); document.write( "The lenght of a rectangular picture is 5 inches greater thatn twice the width. If the perimeter is 112 inches, find the dimensions of the frame.\r
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Algebra.Com's Answer #138958 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Let x = the width
\n" ); document.write( "\"L\" = the length
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\n" ); document.write( "Just write an equation for what it says:
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\n" ); document.write( "\"The length of a rectangular picture is 5 inches greater that twice the width.
\n" ); document.write( "L = 2x + 5
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\n" ); document.write( "\" If the perimeter is 112 inches,\"
\n" ); document.write( "twice the length + twice the width = 112
\n" ); document.write( "2L + 2x = 112
\n" ); document.write( "Simplify, divide equation by 2; the results:
\n" ); document.write( "L + x = 56
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\n" ); document.write( "From the 1st statement, replace L with (2x+5)
\n" ); document.write( "(2x+5) + x = 56
\n" ); document.write( "subtract 5 from both sides
\n" ); document.write( "2x + x = 56 - 5
\n" ); document.write( "3x = 51
\n" ); document.write( "x = \"51%2F3\"
\n" ); document.write( "x = 17 in is the width
\n" ); document.write( "then
\n" ); document.write( "L = 2(17) + 5
\n" ); document.write( "L = 34 + 5
\n" ); document.write( "L = 39 in is the length
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\n" ); document.write( "Check solution by finding the perimeter
\n" ); document.write( "2(39) + 2(17) =
\n" ); document.write( "78 + 34 = 112, confirms our solution
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\n" ); document.write( "Did this make sense? \r
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