document.write( "Question 185243: Can you please help me with this word problem for some reason Im not understanding the concept of figuring these problems.\r
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document.write( "The lenght of a rectangular picture is 5 inches greater thatn twice the width. If the perimeter is 112 inches, find the dimensions of the frame.\r
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document.write( "thanks, \n" );
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Algebra.Com's Answer #138957 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangular picture is 5 inches greater thatn twice the width. If the perimeter is 112 inches, find the dimensions of the frame. \n" ); document.write( "------------------------ \n" ); document.write( "Let the width be \"x\". \n" ); document.write( "Then length = \"2x+5\" \n" ); document.write( "------------------------- \n" ); document.write( "Perimeter = 2(length + width) \n" ); document.write( "112 = 2(2x+5 + x) \n" ); document.write( "56 = 3x+5 \n" ); document.write( "3x = 51 \n" ); document.write( "x = 17 inches (width) \n" ); document.write( "2x+5 = 2*17+5 = 34+5 = 39 inches (length) \n" ); document.write( "============================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |