document.write( "Question 185227: 2x^2-24x+33=0 \n" ); document.write( "

Algebra.Com's Answer #138938 by Edwin McCravy(20055) $\"\"$ $\"About$

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2x^2-24x+33=0
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document.write( "First you try to factor it:\r\n" );
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document.write( "Multiply 2 by 33, getting 66.  Now we make a column of\r\n" );
document.write( "ways to factor 66 using two integers:\r\n" );
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document.write( "factors\r\n" );
document.write( " 1x66\r\n" );
document.write( " 2x33\r\n" );
document.write( " 3x22\r\n" );
document.write( " 6x11\r\n" );
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document.write( "Now since the sign of 66 is positive, we make\r\n" );
document.write( "a list of the sums:\r\n" );
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document.write( "factors      sums of factors\r\n" );
document.write( " 1x66          1+66=67    \r\n" );
document.write( " 2x33          2+33=35 \r\n" );
document.write( " 3x22          3+22=25\r\n" );
document.write( " 6x11          6+11=17\r\n" );
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document.write( "Now you try to find one that agrees in absolute value
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document.write( "with the middle term of \r
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document.write( "2x^2-24x+33=0\r
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document.write( "Oh oh!  There aren't any!  So it won't factor. So we 
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document.write( "have to use the quadratic formula.\r
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document.write( "a=2, b=-24, c=33\r
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document.write( "Factor 2 out of the top\r
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document.write( "Divide top and bottom by 2:\r
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document.write( "Edwin

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