document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185188>Question 185188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a circular diagramme. I draw the first sector,then the second one, which is 2 times bigger than the fist one ,and so on, to finally divide the whole diagramme. If we double the previous sector 6 times, find the value of the angle at the middle of the inital sector. PLEASEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPP PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELPPPPPPPPPPPPPPPPPPP'' </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138910 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first sector is x<BR>\n" );
document.write( "second is 2x<BR>\n" );
document.write( "third is 4x<BR>\n" );
document.write( "fourth is 8x<BR>\n" );
document.write( "fifth is 16x<BR>\n" );
document.write( "sixth is 32x<BR>\n" );
document.write( "last is 64x<BR>\n" );
document.write( "So you have<BR>\n" );
document.write( "(x + 2x + 4x + 8x + 16x + 32x + 64x) =  127x<BR>\n" );
document.write( "there are 360degrees in a circle. So the angle x is 360/127 </SPAN>\n" );
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