document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184561>Question 184561</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977258/algebrahomeworkh>Algebra and trigonometry structure and method</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> If one side of a square is increased by 8 cm and an adjacent side decreased by 2 cm, a rectangle is formed whose perimeter is 40 cm. Find the length of a side of the square </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138907 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the side of the square.\r<BR>\n" );
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document.write( "The new rectangle has sides x + 8 (twice) and x – 2 (twice).\r<BR>\n" );
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document.write( "Therefore the perimeter = 2(x + 8) + 2(x – 2) = 4x + 12.\r<BR>\n" );
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document.write( "Now 4x + 12 = 40; therefore 4x = 28; x = 7.\r<BR>\n" );
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document.write( "The length of a side of the square is 7 cm.<BR>\n" );
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