document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185129>Question 185129</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE SUM OF TWO NUMBERS IS 27. ONE HALF OF THE FIRST NUMBER PLUS ONE THIRD OF THE SECOND NUMBER IS 11. FIND THE NUMBERS. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138900 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=27 MULTIPLY BY -1/2 & ADD.<BR>\n" );
document.write( "X/2+Y/3=11<BR>\n" );
document.write( "-X/2-Y/2=-27/2<BR>\n" );
document.write( "----------------------<BR>\n" );
document.write( "Y/3-Y/2=11-27/2<BR>\n" );
document.write( "(2Y-3Y)/6=(11*2-27)/2<BR>\n" );
document.write( "-Y/6=(22-27)/2<BR>\n" );
document.write( "-Y/6=-5/2<BR>\n" );
document.write( "-2Y=-30<BR>\n" );
document.write( "Y=-30/-2<BR>\n" );
document.write( "Y=15 ANS.<BR>\n" );
document.write( "X+15=27<BR>\n" );
document.write( "X=27-15<BR>\n" );
document.write( "X=12 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "12/2+15/3=11<BR>\n" );
document.write( "6+5=11<BR>\n" );
document.write( "11=11<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );