document.write( "Question 185158: The sum of the squares of two consecutive intergers is 25. \n" ); document.write( "

Algebra.Com's Answer #138893 by vleith(2983) $\"\"$ $\"About$

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let x be one number, then (x+1) is the other number
\n" ); document.write( " $\"x%5E2+%2B+%28x%2B1%29%5E2+=+25\"$
\n" ); document.write( " $\"x%5E2+%2B+x%5E2+%2B+2x+%2B+1+=+25\"$
\n" ); document.write( " $\"2x%5E2+%2B+2x+-24+=+0\"$
\n" ); document.write( " $\"x%5E2+%2B+x+-12+=+0\"$
\n" ); document.write( " $\"%28x%2B4%29%28x-3%29+=+0\"$
\n" ); document.write( "x = -4 and x = 3
\n" ); document.write( "so then numbers are 3,4 and -4,-3 \n" ); document.write( "

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