document.write( "Question 185146: THE ATTENDANCE AT A SCHOOL CONCERT WAS 578.
\n" ); document.write( "ADMISSION COST $2.00 FOR ADULTS AND $1.50 FOR CHILDREN.
\n" ); document.write( "THE RECEIPTS WERE $985.00.
\n" ); document.write( "HOW MANY ADULTS AND HOW MANY CHILDREN ATTENDED THE CONCERT? \n" ); document.write( "
Algebra.Com's Answer #138885 by jigs_ipan(5)\"\" \"About 
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solution:
\n" ); document.write( " let x be the number of adult attented
\n" ); document.write( " let y be the number of children attended\r
\n" ); document.write( "\n" ); document.write( " given:
\n" ); document.write( " cost of adult = $2.00
\n" ); document.write( " cost of child = $1.50\r
\n" ); document.write( "\n" ); document.write( " x + y = 578 (equation 1)
\n" ); document.write( " 2.00x + 1.50y = 985 (equation 2)\r
\n" ); document.write( "\n" ); document.write( " x + y = 578 => x = 578 - y (equation 3)\r
\n" ); document.write( "\n" ); document.write( " 2.00(578 - y) + 1.50y = 985 (substituting the value of x in eq. 1 to eq. 2)
\n" ); document.write( " 1156 - 2.00y + 1.50y = 985
\n" ); document.write( " -2.00y + 1.50y = 985 - 1156
\n" ); document.write( " -0.50y = -171 (diving both sides by -0.50)
\n" ); document.write( " y = 342\r
\n" ); document.write( "\n" ); document.write( " x = 578 - y (eq. 3)
\n" ); document.write( " x = 578 - (342) (substituting the value of y which is 342))
\n" ); document.write( " x = 236\r
\n" ); document.write( "\n" ); document.write( "therefore, the number of adults attended the concert was 236 and the number of children attended was 342...
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