document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=185116>Question 185116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Candy sells for $1.30 per lb is to be mixed with candy selling for $0.90 per lb to get 100 lb of a mix that will sell for $1 per lb. How much of each type should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138880 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the number of lbs selling for 1.30. 100-x lbs selling for .90<BR>\n" );
document.write( "100 lbs selling for $1/lb costs $100.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "1.3x+.9(100-x)=100<BR>\n" );
document.write( "1.3x+90-.9x=100<BR>\n" );
document.write( "0.4x=10<BR>\n" );
document.write( "x=25 lbs<BR>\n" );
document.write( "75 lbs selling for .90<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );