document.write( "Question 185084: SOLVE for x:\r
\n" ); document.write( "\n" ); document.write( "a) logbase3 x + logbase3 (x-8)=2
\n" ); document.write( "b) logbase4 (x+2)+logbase4(x-4)=2
\n" ); document.write( "c) logbase2 (5x-2)-logbase2 2 =1/2 logbase2 36 + 2 logbase2 3
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Algebra.Com's Answer #138860 by edjones(8007)\"\" \"About 
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a)
\n" ); document.write( "logbase3 x + logbase3 (x-8)=2
\n" ); document.write( "3^log[3]x * 3^log[3](x-8)=3^2
\n" ); document.write( "x(x-8)=9
\n" ); document.write( "x^2-8x-9=0
\n" ); document.write( "(x-9)(x+1)=0
\n" ); document.write( "x=9, x<>-1 because there is no log of a negative number.
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\n" ); document.write( "b)
\n" ); document.write( "logbase4 (x+2)+logbase4(x-4)=2
\n" ); document.write( "4^log[4](x+2) * 4^log[4](x-4)=4^2
\n" ); document.write( "(x+2)(x-4)=16
\n" ); document.write( "x^2-2x-8=16
\n" ); document.write( "x^2-2x-24=0
\n" ); document.write( "(x-6)(x+4)=0
\n" ); document.write( "x=6
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\n" ); document.write( "c)
\n" ); document.write( "logbase2 (5x-2)-logbase2 2 =1/2 logbase2 36 + 2 logbase2 3
\n" ); document.write( "2^log[2](5x-2) / 2^log[2]2=2^log[2]6 * 2^log[2]9 explanation:{1/2 log 36= sqrt(36)}
\n" ); document.write( "(5x-2)/2=6*9
\n" ); document.write( "5x-2=108
\n" ); document.write( "5x=110
\n" ); document.write( "x=22
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\n" ); document.write( "Ed
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