document.write( "Question 185098: Sean mows his half of hte yard in 30 minutes. His brother takes 50 minutes. If they each had their own lawn mower and worked together, how long would the job take? \n" ); document.write( "
Algebra.Com's Answer #138850 by stanbon(75887)\"\" \"About 
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Sean mows his half of the yard in 30 minutes. His brother takes 50 minutes. If they each had their own lawn mower and worked together, how long would the job take?
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\n" ); document.write( "Sean DATA:
\n" ); document.write( "time = 30 min/job ; rate = 1/30 job/min
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\n" ); document.write( "Brother DATA:
\n" ); document.write( "time = 50 min/job ; rate = 1/50 job/min
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\n" ); document.write( "Together DATA:
\n" ); document.write( "time = x min/job ; rate = 1/x job/min
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\n" ); document.write( "Equation:
\n" ); document.write( "rate + rate = together rate
\n" ); document.write( "1/30 + 1/50 = 1/x\r
\n" ); document.write( "\n" ); document.write( "To get rid of the denominators,
\n" ); document.write( "multiply thru by 150x to get:
\n" ); document.write( "5x + 3x = 150
\n" ); document.write( "8x = 150
\n" ); document.write( "x = 150/8 = 18 3/4 minutes (time to do the job together)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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