document.write( "Question 25799: solve the following application problem\r
\n" ); document.write( "\n" ); document.write( "the local movie theater sold 100 tickets for $390. If children's tickets cost $3 and adult tickets $6, how many of each were sold?\r
\n" ); document.write( "\n" ); document.write( " 3c+6a=390
\n" ); document.write( " -3c -3c
\n" ); document.write( " 6a=390-3c
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Algebra.Com's Answer #13884 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
LEt the cjilderns tickets be x
\n" ); document.write( " let the adults tickets be y
\n" ); document.write( "Now x+y=100 Solve for y
\n" ); document.write( "y=100-x
\n" ); document.write( "Childern tickets = $3
\n" ); document.write( "Adults = $6
\n" ); document.write( "3x+6y=390 (SUBSITUTE)
\n" ); document.write( "3x+6(100-x)=390
\n" ); document.write( "3x+600-6x=390
\n" ); document.write( "-3x=-210
\n" ); document.write( "x=70
\n" ); document.write( "y=100-70
\n" ); document.write( "y=30\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, about 70 childern tickets were sold, and about 30 adults tickets were sold.
\n" ); document.write( "Paul.
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