document.write( "Question 25799: solve the following application problem\r
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document.write( "the local movie theater sold 100 tickets for $390. If children's tickets cost $3 and adult tickets $6, how many of each were sold?\r
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document.write( " 3c+6a=390
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document.write( " -3c -3c
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document.write( " 6a=390-3c
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Algebra.Com's Answer #13884 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! LEt the cjilderns tickets be x \n" ); document.write( " let the adults tickets be y \n" ); document.write( "Now x+y=100 Solve for y \n" ); document.write( "y=100-x \n" ); document.write( "Childern tickets = $3 \n" ); document.write( "Adults = $6 \n" ); document.write( "3x+6y=390 (SUBSITUTE) \n" ); document.write( "3x+6(100-x)=390 \n" ); document.write( "3x+600-6x=390 \n" ); document.write( "-3x=-210 \n" ); document.write( "x=70 \n" ); document.write( "y=100-70 \n" ); document.write( "y=30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, about 70 childern tickets were sold, and about 30 adults tickets were sold. \n" ); document.write( "Paul. \n" ); document.write( " |