document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25795>Question 25795</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: p^2+6p=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13881 by </B><A HREF=/tutors/aboutme.mpl?userid=jb007mi6><B>jb007mi6(53)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jb007mi6><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ok ... so you have p common in both terms on the left hand side of the equation\r<BR>\n" );
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document.write( "this means you can factor the p like so p(p+6)=0 if you expand the LHS, then you will get the original equation.\r<BR>\n" );
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document.write( "now set each factor equal to 0\r<BR>\n" );
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document.write( "p=0 and p+6=0\r<BR>\n" );
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document.write( "thus, \r<BR>\n" );
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document.write( "p=0 and p=-6\r<BR>\n" );
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document.write( "hope this helps... </SPAN>\n" );
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