document.write( "Question 184911: an airplane flew for 5 hours with a tail wind of 25 km/h.
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document.write( "the return flight against the same wind took 5.5 hours.
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document.write( "find the speed of the airplane in still air. \n" );
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Algebra.Com's Answer #138784 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "THE DISTANCES ARE THE SAME THUS: \n" ); document.write( "RT=RT \n" ); document.write( "(X+25)5=(X-25)5.5 \n" ); document.write( "5X+125=5.5X-137.5 \n" ); document.write( "5X-5.5X=-137.5-125 \n" ); document.write( "-.5X=-262.5 \n" ); document.write( "X=-262.5/-.5 \n" ); document.write( "X=525 MPH IS THE PLANE SPEED IN STILL AIR.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |