document.write( "Question 184911: an airplane flew for 5 hours with a tail wind of 25 km/h.
\n" ); document.write( "the return flight against the same wind took 5.5 hours.
\n" ); document.write( "find the speed of the airplane in still air.
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Algebra.Com's Answer #138784 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT
\n" ); document.write( "THE DISTANCES ARE THE SAME THUS:
\n" ); document.write( "RT=RT
\n" ); document.write( "(X+25)5=(X-25)5.5
\n" ); document.write( "5X+125=5.5X-137.5
\n" ); document.write( "5X-5.5X=-137.5-125
\n" ); document.write( "-.5X=-262.5
\n" ); document.write( "X=-262.5/-.5
\n" ); document.write( "X=525 MPH IS THE PLANE SPEED IN STILL AIR.\r
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