document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=25794>Question 25794</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of Nora's age and her grandmother's age is 71. Four times Nora's age is 6 less than her grandmother's age. Find their ages. I've tried: <BR>\n" );
document.write( "                            N=Nora g=grandmother<BR>\n" );
document.write( "                            N+g=71<BR>\n" );
document.write( "                            4N=g-6<BR>\n" );
document.write( "                               ?<BR>\n" );
document.write( "PLEASE HELP!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13878 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13878\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Nora's age = x<BR>\n" );
document.write( "Grandma's age = y<BR>\n" );
document.write( "Now x+y=71 Solve for y<BR>\n" );
document.write( "y=71-x<BR>\n" );
document.write( "Four times nora's aage = 4x<BR>\n" );
document.write( "6 less than grandma's age = y-6<BR>\n" );
document.write( "4x=y-6 (subsitute)<BR>\n" );
document.write( "4x=(71-x)-6<BR>\n" );
document.write( "4x=65-x<BR>\n" );
document.write( "5x=65<BR>\n" );
document.write( "x=13<BR>\n" );
document.write( "y=71-13<BR>\n" );
document.write( "y=58\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Hence, nora is 13 years old and her grandma is 58 years old. <BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );