document.write( "Question 184833: Coffee that sells for $3.40 per pound is mixed with coffee that sells for $4.50 per pound in order to create 6 pounds of a blend that sells for $4.06 per pound. How much of each was used to create the new mixture? \n" ); document.write( "
Algebra.Com's Answer #138777 by ankor@dixie-net.com(22740)\"\" \"About 
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Coffee that sells for $3.40 per pound is mixed with coffee that sells for
\n" ); document.write( " $4.50 per pound in order to create 6 pounds of a blend that sells for $4.06
\n" ); document.write( " per pound. How much of each was used to create the new mixture?
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\n" ); document.write( "Let x = amt of $4.50/lb coffee
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\n" ); document.write( "we are told that the total amt resulting from mixing these two quantities is 6 lb, therefore:
\n" ); document.write( "(6-x) = amt of $3.40/lb coffee
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\n" ); document.write( "A typical mixture equation:
\n" ); document.write( "4.5x + 3.4(6-x) = 4.06(6)
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\n" ); document.write( "4.5x + 20.4 - 3.4x = 24.36
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\n" ); document.write( "4.5x - 3.4x = 24.36 - 20.4
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\n" ); document.write( "1.1x = 3.96
\n" ); document.write( "x = \"3.96%2F1.1\"
\n" ); document.write( "x = 3.6 lb of $4.50/lb coffee
\n" ); document.write( "and
\n" ); document.write( "6 - 3.6 = 2.4 lb of $3.40/lb coffee
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\n" ); document.write( "Check the math in the original equation:
\n" ); document.write( "4.5(3.6) + 3.4(2.4) = 4.06(6)
\n" ); document.write( "16.2 + 18.16 = 24.36; equality reigns, a good solution \n" ); document.write( "
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