document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184913>Question 184913</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which is the sum of the infinite progression 3/2, 1, 2/3, 4/9 ......?\r<BR>\n" );
document.write( "\n" );
document.write( "Please put the solution, if it's possible.. thanks in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138761 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138761\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the sum of the infinite progression 3/2, 1, 2/3, 4/9 ......?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "This is a geometric progression and the sum to infinity for geometric progressions when the magnitude of the ratio is less than 1 is a/(1-r), where a is the first term and r is the ratio.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "In this example, a = 3/2, r = 2/3, therefore 1-r = 1/3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Therefore, the sum to infinity = (3/2)/(1/3) = (3 x 3)/(2 x 1) = 9/2 = 4.5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );