document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=184845>Question 184845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of an equilateral triangle with a height of 6 square root 3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #138752 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=138752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h=6sqrt(3)<BR>\n" );
document.write( "The altitude divides the triangle into 2 equal right triangles.<BR>\n" );
document.write( "Each right triangle has angels of 90, 60, and 30 degrees.<BR>\n" );
document.write( "The sides are in the ratio of base 1, hopotenuse 2 and height sqrt(3). (SAT question frequently)<BR>\n" );
document.write( "In our case the base is 6*1, hypotenuse 6*2 and height 6sqrt(3) or 6, 12, 6sqrt(3).<BR>\n" );
document.write( "A=.5hb<BR>\n" );
document.write( "=.5*6sqrt(3)*6<BR>\n" );
document.write( "=18sqrt(3)<BR>\n" );
document.write( "So for the entire equilateral triangle we double the area of the right triangle.<BR>\n" );
document.write( "36sqrt(3) Answer<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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